A block of mass m moves with a velocity of v0 up the plane. The angle of inclination is such that the block is able to slide down. Find the velocity of the block v1, when it returns to the same point at which it was launched. Take mkas the coefficient of friction between the plane and the block.
= v0 ((1 - mk ctn q)/(1+
mk ctn q))0.5
where ctn is cotangent
The free body diagram
of the block is as shown in the figure.
the velocity of the block at
A as v0.
The net force on the
block when it is moving downwards is
The velocity of the
block when it returns to the same position at which it was launched is