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If block A moves downwards at a velocity of 5 ft/s while the cords is free to move on the pulley. Determine the velocity of block B, assume that the mass of the cord is negligible. 1) 5 ft/s |
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Let SA be the distance of the block A from the datum line and SB be the distance of the block B from the datum line. So the total lenght of the cord L, L = SA + LCD + SB, differentiating with respect to time we have VA + VB = 0, VB = -VA = -5 ft/s So, the upward velocity of B, VB = 5 ft/s. |