A crate having a mass of 200 kg, is subjected to two forces. If it is originally at rest, determine the distance it slides in order to attain a speed of 3 m/s. The coefficient of kinetic friction between the crate and the surface is m_{k} = 0.25. 1) 2.34 m 

Equation of motion:
Since the crate slides, the friction force developed between the crate
and its constant surface is Principle of work
and energy : The horizontal component of force 400 N and 500 N which act
in the direction of displacement does positive work. The normal reaction
N, the vertical component of force 500 N and the weight of the crate do
not displace hence do not work.Since the crate is originally at rest T_{1}
= 0. Applying the conservation of energy principle we have: So the distance it
slides in order to attain a speed of 