A ball which weigh's about 25 kg is subjected to an average horizontal force of 300 N. The ball is stationed on a platform 10 km from the ground, determine the range of the projectile if the impact time of the subjected force is 2 s. The range of the projectile is measured from the end of the platform A to where the projectile strikes the ground at B. 1) 1.08 km 

Applying the equation
of motion to the ball we have Considering the vertical
motion, the vertical component of initial veloctiy is (v_{o})_{y}
= 0. The initial and final position is (s_{o})_{y} = 0
and s_{y} = 10km, respectively. By considering the
horizontal motion, the horizontal component of velocity is (v_{o})_{x}
= 24 m/s. The initial and final position are (s_{o})_{x}
= 0 and s_{x} So the range of the projectile is R = 1.08 km 