Determine the velocity
after a time of 6 s if the horizontal traction F varies with time as
F = 36(t-1) + 36 as shown in the figure of a 25 Mg car. The car is originally
at rest.

1) 0.051 m/s
2) 0.075 m/s
3) 0.032 m/s
4) 0.023 m/s

The equation of motion
can be written as
m (v_{x})_{1} + S F_{y}
dt = m (v_{x})_{2}
0 + int(0 to 4)(36(t-1) + 36) dt = 25 (10^{3})v
v = 0.051 m/s = 0.051 m/s

So, the velocity of the car after a time of 6 s is
v = 0.051 m/s