Two
trains are running in the same directions.Train A is ahead of train B by
1 km at t=0. The velocity equation of train A is given by V = 10t . The
acceleration equation for train B is a = 45 . After some time they meet
at a station and a person gets down from B to meet a friend in A.The station
is 61000m from starting point of train B.The person had to wait for some
time,so that the train carrying his friend arrives at the station, where
it is instantaneously brought to stop.Calculate the time he had to wait. 1) 52.068 s. 2) 12.234 s. 3) 25.489 s. 4) 67.328 s. 

Train A 