During
a snow avalanche,which slides down a curved ramp with mass of 1000 kgs,faces
a coefficient of kinetic friction m_{k}
= 0.2.If it gathers a speed of 5m/s by the time it reaches point A,determine
the normal force on the ground due to it,and the rate of increase of its
speed.The equation of the slope is y = 0.08x^{2}. 1) N = 862.07 N, a_{t} = 9.618 m/s^{2}. 2) N = 217.45 N, a_{t} = 12.825 m/s^{2}. 3) N = 123.45 N, a_{t} = 10. 286 m/s^{2}. 4) N = 678.48 N, a_{t} = 4.124 m/s^{2}. 

For the
given equation  Equations of motion N  9810 cos 86.42 = 1000(25/100.195) N = 862.07 N. 0.2(862.07) + 9810 sin 86.42 = 1000 a_{t} a_{t} = 9.618 m/s^{2}. 