During a snow avalanche,which slides down a curved ramp with mass of 1000 kgs,faces a coefficient of kinetic friction mk = 0.2.If it gathers a speed of 5m/s by the time it reaches point A,determine the normal force on the ground due to it,and the rate of increase of its speed.The equation of the slope is y = 0.08x2.
1) N = 862.07 N,
at = 9.618 m/s2.
2) N = 217.45 N,
at = 12.825 m/s2.
3) N = 123.45 N,
at = 10. 286 m/s2.
4) N = 678.48 N,
at = 4.124 m/s2.
For the given equation -


Equations of motion-
N - 9810 cos 86.42 = 1000(25/100.195)
N = 862.07 N.

-0.2(862.07) + 9810 sin 86.42 = 1000 at
at = 9.618 m/s2.