Determine the velocity of the 15 kg block A after it moves 1 m down the plane.Block B has a mass of 5 kg and the coefficient of kinetic friction between the plane and block A is = 0.3. Find the tension in the cord.

1) 2.38 m/s, 63.21 N.
2) 1.23 m/s, 21.24 N.
3) 5.67 m/s, 12.45 N.
4) 7.54 m/s, 23.45 N.

Block A:
Fy = 0;
NA - 15(9.81)cos 40 = 0;
NA = 112.734N.

System:
T1 + U1-2 = T2
0 + 15(9.81)(sin 40)1 - 0.3(112.7)(1) - 5(9.81)(1) = (1/2)(15)v2 + (1/2)(5)v2.
v = 2.38 m/s.

Block B:
T1 + U1-2 = T2
0 + T(1) - 5(9.81)(1) = (1/2)(5)(2.38)2
T = 63.21 N.

Also for block A:
T1 + U1-2 = T2
0 = 15(9.91)(sin 40)(1) - T(1) -0.3(112.7)(1) = (1/2)(15)(2.38)2

T = 63.21 N.