In a manufacturing plant,products having a weight of 25 kg are delivered to the chute at vA =2 m/s using a conveyer belt. Determine their speeds when they reach points B,C,D. Neglect friction between the products and the chute surface.

1) 1.23 m/s, 4.56 m/s, 6.78 m/s.
2) 3.26 m/s, 13.91 m/s, 14.15 m/s.
3) 12.54 m/s, 11.68 m/s, 9.34 m/s.
4) 10.27 m/s, 13.57 m/s, 15.46 m/s.
TA + UA-B = TB
(1/2)(25)(2)2 + (25)(9.81)(10)(1-cos15o) = (1/2)(25)vB2
vB = 3.26 m/s.

TA + UA-C = TC
(1/2)(25)(2)2 + 25(9.81)(10cos15o) = (1/2)(25)vC2.
vC = 13.91 m/s.

TA + UA-D = TD
(1/2)(25)(2)2 + 25(9.81)(10) = (1/2)(25)vD2
vD = 14.15 m/s.