CS 54 - Lab 8

Lab Assignment

The RARO is Automobile Rip Offs (RARO) Management Team just got out of a meeting with the Enhanced Uniform Learning Ripoffs (EULER) Team from Mathematically Obfuscated Analysis of Nuances (MOAN). The EULER team derived that customers could be scored based on the following formula:
y = 5k - 2(k - v)
where k is the length of the customer's name and v is the number of vowels in the customer's name. The EULER team also determined that customers with 4, 8, 12, … letters in their names were bad luck, so they would be assigned a score of -1.

Lab Assignment - Part I (Required - 8 Points)

RARO wants you to write two functions to analyze customer names:

• unsigned int numVowels(char customerName[]);
  1. Iterates through customerName and counts the number of vowels.
  2. Returns the number of vowels found.
• unsigned int nameLength(char customerName[]);
  1. Iterates through customerName and counts the number of characters excluding the NUL character ('\0').
  2. Returns the number of characters found.
• int scoreName(char customerName[]);
  1. Use the formula above to score the name.
  2. If the length of the name is a multiple of 4, then return -1; else return the score.

In your main() function, ask the user for a customer name to test, and report the number of vowels, the length of the name, and the score of the customer's name.

Lab Assignment - Part II (Quasi Required - 10 Points)

The EULER Team determined the average amount the customer spends can be modeled using this formula:
s = k y² + vy
RARO wants you to find total spent based on this for 6 non trivial customer names.

Lab Assignment - Part III (Extra Credit - 12 Points)

RARO now wants you to integrate this into your previous work by putting the score into the struct you used before:
struct customer
{
  unsigned int customerID;
  string name;
  double amountSpent;
  unsigned short numTimesRippedOff;
  int nameScore; /* NOTE: new member of the struct */
};

Take your previous work (from lab 07) and make the following changes to integrate the two pieces together:

• In makeCustomer(), call scoreName() to calculate the score. Assign calculated value to the new customer's nameScore.
• Print out the customer's name score along with the other four attributes that were already being printed.

The real challenge here is the conflict of interest: the name in the struct is a string and the functions above take NUL Terminated Character Arrays. This is the underlying problem I want you to attack. You will need convert the name from a string to a NUL Terminated Character Array OR change the name in the struct to be a NUL Terminated Character Array and adjust the rest of your lab 07 accordingly to handle name as a NUL Terminated Character Array. You may use my model solution for lab 07 if you prefer to build on that instead of your own lab.

Grading & Submission

Part I is worth 8 points. Part II is worth 10 points (Part I + 2 more points). Part III is worth 12 points (Part II + 2 points extra credit). The lab is out of 10 points. When you're done, submit your lab08.tar.gz file on Blackboard. I will be grading your program on the following criteria:

• Correctness - 70%
  1. Does it compile?
  2. Does it work?
  3. Are there any bugs?
  
  
• Coding Style - 30%
  1. Each level of indentation is two spaces.
  2. The program is commented.
  3. The program conforms to the coding standards as outlined by the CS 54 Style Guide.