An Analogy for Chemical Equilibrium,DG, and DG°
(view Simulation of this process)
We will consider the apparatus below as a chemical reactor in which we can carry out the reaction:
H2O(left)
-> H2O(right)
We will work with 90 cm3of water, which is approximately 5.0 moles.
Note that the cylinder on
the right has a larger diameter than the cylinder on the left.
We will take the area of the
left cylinder as 10 cm2, and that of the right cylinder as
20cm2.
We can start with all of
the water on either the left or the right.

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When the stopcock is opened,the outcome will be the same:

This is the nature of
Chemical Equilibrium -
whether you start with only
reactants or only products,
the system comes to
equilibrium to satisfy some inherent property.
The equilibrium condition
could have been determined by the relative volumes,
relative masses, relative
potential energy, or some other property of the system.
In this case, the
equilibrium is determined by the relative height of the liquid
in the two cylinders.
(More precisely, the equilibrium is determined by equal pressures on both sides of the stopcock.)
Irrespective of the
starting condition, water will move from the cylinder
with the higher level to the
cylinder with the lower level.
In a chemical system at
fixed temperature and pressure,
the reaction proceeds so as to
lower the Gibbs Free Energy (G) of the system.
The equilibrium condition
is determined by the minimum free energy of the system.
However, our description of
the equilibrium condition involves
an equilibrium constant (K)
which is related to
the relative amounts of the
reactants and products.
The situation is further
complicated by the fact that the value of the equilibrium constant
is determined by the Gibbs
free energy required (DGo)
to convert a specific amount
of
reactants to a specific amount of products
(specified by the balanced
chemical reaction).
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Let's try to apply the ideas
of
chemical equilibrium to this very simple system.
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In this very simple case of a
"reaction",
H2O(left) -> H2O(right)
there is no difference
between Gibbs Free Energy (G) and Potential Energy (E),
so we will work with the
simpler quantity, E.
The potential energy of an
object is the product of its mass (m),
the gravitational constant (g=
9.80 m/sec2), and the height of its center of gravity (h):
E = mgh .
Using mass values in grams
and height values in meters
gives the potential energy
in milliJoules (mJ).
For a column of water of height H(meters), volume V (cm3), and Density (g/cm3):
m = DV ; h = H/2
E = gDVH/2 .
The energy is different in the left and right columns,
EL = gDVLHL/2 ; ER = gDVRHR/2
Etotal = EL+ ER = (gD/2)(VLHL + VRHR)
While the transfer is most
easily considered in terms of volume,
Chemists prefer to work
with the Chemical Amount (moles):
moles = DV/M (M =Molar Mass in grams) .
We can then describe the energies on the left and right in molar terms:
(Em)L =gMHL/2 ; (Em)R= gMHR/2
The difference between
these two terms is called DErx:
DErx=(Em)R
- (Em)L = (gM/2)(HR- HL)
Now we consider the changes
in these quantities as we allow the liquid
to flow from left to right
until it reaches equilibrium,
then we will force all of
the liquid to the right.

The equilibrium condition
of equal heights of the two columns
now has two additional
conditions:
1. The total energy
hasa minimum value at this point.
2. The energy/mole has the
same value in both columns.
The quantity DErx is related to the driving force of the
process
(the difference in heights
of the two columns):
When this quantity is
negative, the "reaction" proceeds as it is written
H2O(left)
-> H2O(right)
and if this quantity is
positive the reverse "reaction" is favored.
While chemical reactions
are much more complex than this simple transfer,
the equilibrium condition
is very similar:
1. The total Gibbs Free
Energy of the system has a minimum value at equilibrium.
2. The sums of the Partial
Molar Gibbs Free Energies (Chemical Potentials) are
the same for the Reactants
and the Products (each multiplied by its
stoichiometric constant).
A quantity DGrx is defined as the difference between the
molar Gibbs free energies
of the products and the
molar Gibbs free energies
of the reactants.
When this quantity is
negative, the reaction proceeds as it is written,
and if this quantity is
positive, the reverse reaction is favored.
One other point may be made
about this system:
The standard energy change (DE°) for the reaction
H2O(left)
-> H2O(right)
is given by the difference
in the molar energy when all of the water
is on the right (3.97
mJ/mole) and when all of the water is on the left
(7.94 mJ/mole):
DE°= - 3.97 mJ/mole
This represents the energy
(mechanical work) per mole of water
required to convert
the initial state (all on the left) to
the final state (all on
the right).
* * * * * * * * * * * * * * ** * *
For Chemical Reactions,
there is a DG°, which represents the
Chemical Work required to
convert the reactants
completely to the products
at constant T & P.
This quantity is not to be
confused with DGrx, which represents the
Chemical work required to
make this conversion
while the reaction is
in progress.
If DG°is negative, the equilibrium condition
will
favor
products over reactants
and the opposite is true if DG° is positive.
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