Special Project #2 : The Gearbox II

		Tire:
 
			Tread width = 165 mm = 6.5 in.
			Ratio of sidewall height to tread width = 80
			Wheel diameter = 13 in.
			Sidewall height = (80%)*(165) = 132 mm = 5.2 in.
			Radius = (13 in)*(0.5) + (5.2 in.) = 11.7 in.
 
			Differential gear ratio = 37:13
			4th Gear ratio = 0.96 (from Project #1)	
			65 mi/hr = 68625.33 in/min
	

		Calculations:
	
			v = (angular velocity)*(radius)

			angular velocity = v / radius
				 = (68625.33 in/min)/(11.7 in.)
				 = 5865.41 rad/min
				 = 933.51 rev/min
		
		
			(angular velocity of engine)/933.51 = 37/13
		 
			angular velocity of engine = 2657 rev/min		
	
			(angular velocity of engine)*(4th Gear ratio)

 			= (2657 rev/min)*(0.96)
			= 2551 rev/min

		Answer = 2551 RPM

BE 150 HOMEPAGE
PROJECT #1


Last Update: 07/23/1997