Determining
the Empirical Formula of Magnesium
Oxide
Note: mass of O = total mass – mass
Mg
= 0.585 g – 0.353 g = 0.232 g
then
% Mg = (mass Mg ÷ total
mass MgxOy) ´ 102
= (0.353 g ÷ 0.585 g) ´ 102 = 60.3 %
% O = (mass O ÷ total
mass MgxOy) ´ 102
= (0.232 g ÷ 0.585 g) ´ 102 = 39.7 %