Zn(s) +
2 HCl(aq) ----> ZnCl2(aq) +
H2(g)
2 Al(s) +
6 HCl(aq) ----> 2 AlCl3(aq) +
3 H2(g)
Cu(s) +
n HCl(aq) --x--> no reaction
Note: Cu is
below H (0.00 V ref) in table, so
It will not react with acids H+(aq) to form H2(g)
Metals above H in the table will react with acids.