Determining the Empirical Formula of Magnesium
Oxide
Note:
mass of O = total mass
– mass Mg
= 0.585 g – 0.353 g = 0.232 g
then
% Mg
= (mass Mg ÷ total mass MgxOy) ´ 102
=
(0.353 g ÷ 0.585 g) ´ 102 = 60.3 %
% O =
(mass O ÷ total mass MgxOy) ´ 102
=
(0.232 g ÷ 0.585 g) ´ 102 = 39.7 %
Mg = 60.3 %
andO
= 39.7 %
andO
= 39.7 %