Zn(s) + 2 HCl(aq) ----> ZnCl2(aq) + H2(g)
2 Al(s) + 6 HCl(aq) ----> 2 AlCl3(aq) + 3 H2(g)
Cu(s) + n HCl(aq) --x--> no reaction
Note:
Cu is below H (0.00 V ref) in table, so
It will not react with acids H+(aq) to form H2(g)
Metals above H in the table will react with
acids.